7n+2[3(1-n)-2(1+n)]=4

Solution for 7n+2[3(1-n)-2(1+n)]=4 equation:

Simplifying
7n + 2[3(1 + -1n) + -2(1 + n)] = 4
7n + 2[(1 * 3 + -1n * 3) + -2(1 + n)] = 4
7n + 2[(3 + -3n) + -2(1 + n)] = 4
7n + 2[3 + -3n + (1 * -2 + n * -2)] = 4
7n + 2[3 + -3n + (-2 + -2n)] = 4

Reorder the terms:
7n + 2[3 + -2 + -3n + -2n] = 4

Combine like terms: 3 + -2 = 1
7n + 2[1 + -3n + -2n] = 4

Combine like terms: -3n + -2n = -5n
7n + 2[1 + -5n] = 4
7n + [1 * 2 + -5n * 2] = 4
7n + [2 + -10n] = 4

Reorder the terms:
2 + 7n + -10n = 4

Combine like terms: 7n + -10n = -3n
2 + -3n = 4

Solving
2 + -3n = 4

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -3n = 4 + -2

Combine like terms: 2 + -2 = 0
0 + -3n = 4 + -2
-3n = 4 + -2

Combine like terms: 4 + -2 = 2
-3n = 2

Divide each side by '-3'.
n = -0.6666666667

Simplifying
n = -0.6666666667